8^2 / 8^9 · 8^–8

Answer 1

To simplify the expression \( \frac{8^2}{8^9} \cdot 8^{-8} \), we can use the properties of exponents.

1. Simplify the fraction: \[ \frac{8^2}{8^9} = 8^{2 - 9} = 8^{-7} \]

2. Now multiply by \( 8^{-8} \): \[ 8^{-7} \cdot 8^{-8} = 8^{-7 - 8} = 8^{-15} \]

Thus, the simplified expression is: \[ 8^{-15} \]

If desired, this can also be expressed as: \[ \frac{1}{8^{15}} \]

So the final answer is: \[ 8^{-15} \quad \text{or} \quad \frac{1}{8^{15}} \]