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Inspired by a video, Brooke decided to try a Filipino chicken recipe. The recipe requires 2 1/2 pounds of chicken. Brooke bough...Question
Inspired by a video, Brooke decided to try a Filipino chicken recipe. The recipe requires 2 1/2
pounds of chicken. Brooke bought 5 3/4
pounds of chicken. How many pounds of chicken remain unused
pounds of chicken. Brooke bought 5 3/4
pounds of chicken. How many pounds of chicken remain unused
Answers
Answered by
GPT-4o mini
To find out how many pounds of chicken remain unused, we need to subtract the amount of chicken required for the recipe from the amount Brooke bought.
Brooke bought \( 5 \frac{3}{4} \) pounds of chicken, and the recipe requires \( 2 \frac{1}{2} \) pounds of chicken.
First, we'll convert these mixed numbers to improper fractions:
1. For \( 5 \frac{3}{4} \):
\[
5 \frac{3}{4} = 5 + \frac{3}{4} = \frac{5 \times 4 + 3}{4} = \frac{20 + 3}{4} = \frac{23}{4}
\]
2. For \( 2 \frac{1}{2} \):
\[
2 \frac{1}{2} = 2 + \frac{1}{2} = \frac{2 \times 2 + 1}{2} = \frac{4 + 1}{2} = \frac{5}{2}
\]
Now, we need to calculate how much chicken remains after using the required amount for the recipe:
\[
\text{Remaining chicken} = \text{Amount bought} - \text{Amount used}
\]
This can be written as:
\[
\text{Remaining chicken} = \frac{23}{4} - \frac{5}{2}
\]
To subtract these fractions, we need a common denominator. The least common multiple of 4 and 2 is 4. We convert \( \frac{5}{2} \) to a fraction with a denominator of 4:
\[
\frac{5}{2} = \frac{5 \times 2}{2 \times 2} = \frac{10}{4}
\]
Now we can perform the subtraction:
\[
\text{Remaining chicken} = \frac{23}{4} - \frac{10}{4} = \frac{23 - 10}{4} = \frac{13}{4}
\]
Finally, we can convert \( \frac{13}{4} \) back to a mixed number:
\[
\frac{13}{4} = 3 \frac{1}{4}
\]
Thus, the amount of chicken that remains unused is \( 3 \frac{1}{4} \) pounds.
Brooke bought \( 5 \frac{3}{4} \) pounds of chicken, and the recipe requires \( 2 \frac{1}{2} \) pounds of chicken.
First, we'll convert these mixed numbers to improper fractions:
1. For \( 5 \frac{3}{4} \):
\[
5 \frac{3}{4} = 5 + \frac{3}{4} = \frac{5 \times 4 + 3}{4} = \frac{20 + 3}{4} = \frac{23}{4}
\]
2. For \( 2 \frac{1}{2} \):
\[
2 \frac{1}{2} = 2 + \frac{1}{2} = \frac{2 \times 2 + 1}{2} = \frac{4 + 1}{2} = \frac{5}{2}
\]
Now, we need to calculate how much chicken remains after using the required amount for the recipe:
\[
\text{Remaining chicken} = \text{Amount bought} - \text{Amount used}
\]
This can be written as:
\[
\text{Remaining chicken} = \frac{23}{4} - \frac{5}{2}
\]
To subtract these fractions, we need a common denominator. The least common multiple of 4 and 2 is 4. We convert \( \frac{5}{2} \) to a fraction with a denominator of 4:
\[
\frac{5}{2} = \frac{5 \times 2}{2 \times 2} = \frac{10}{4}
\]
Now we can perform the subtraction:
\[
\text{Remaining chicken} = \frac{23}{4} - \frac{10}{4} = \frac{23 - 10}{4} = \frac{13}{4}
\]
Finally, we can convert \( \frac{13}{4} \) back to a mixed number:
\[
\frac{13}{4} = 3 \frac{1}{4}
\]
Thus, the amount of chicken that remains unused is \( 3 \frac{1}{4} \) pounds.