Question
Jamal made a salad that uses 3/4
of a pound of lettuce, 1 1/2
pounds of tomatoes, and 5/6
of a pound of cheese. In order to see how much the finished salad would weigh, what operation would you use?
of a pound of lettuce, 1 1/2
pounds of tomatoes, and 5/6
of a pound of cheese. In order to see how much the finished salad would weigh, what operation would you use?
Answers
Answered by
GPT-4o mini
To find the total weight of the finished salad, you need to add the weights of each ingredient together. You would perform the following addition:
1. Weight of lettuce: \( \frac{3}{4} \) pound
2. Weight of tomatoes: \( 1 \frac{1}{2} \) pounds, which can be converted to an improper fraction: \( \frac{3}{2} \) pounds
3. Weight of cheese: \( \frac{5}{6} \) pound
Now, you would add these fractions together:
\[
\frac{3}{4} + \frac{3}{2} + \frac{5}{6}
\]
To add these fractions, you will first need to find a common denominator. The least common multiple of 4, 2, and 6 is 12. Then, convert each fraction to have a denominator of 12:
1. \( \frac{3}{4} = \frac{3 \times 3}{4 \times 3} = \frac{9}{12} \)
2. \( \frac{3}{2} = \frac{3 \times 6}{2 \times 6} = \frac{18}{12} \)
3. \( \frac{5}{6} = \frac{5 \times 2}{6 \times 2} = \frac{10}{12} \)
Now add these fractions:
\[
\frac{9}{12} + \frac{18}{12} + \frac{10}{12} = \frac{9 + 18 + 10}{12} = \frac{37}{12}
\]
So, you would add the weights of the lettuce, tomatoes, and cheese together to find the total weight of the salad. The operation used would be addition.
1. Weight of lettuce: \( \frac{3}{4} \) pound
2. Weight of tomatoes: \( 1 \frac{1}{2} \) pounds, which can be converted to an improper fraction: \( \frac{3}{2} \) pounds
3. Weight of cheese: \( \frac{5}{6} \) pound
Now, you would add these fractions together:
\[
\frac{3}{4} + \frac{3}{2} + \frac{5}{6}
\]
To add these fractions, you will first need to find a common denominator. The least common multiple of 4, 2, and 6 is 12. Then, convert each fraction to have a denominator of 12:
1. \( \frac{3}{4} = \frac{3 \times 3}{4 \times 3} = \frac{9}{12} \)
2. \( \frac{3}{2} = \frac{3 \times 6}{2 \times 6} = \frac{18}{12} \)
3. \( \frac{5}{6} = \frac{5 \times 2}{6 \times 2} = \frac{10}{12} \)
Now add these fractions:
\[
\frac{9}{12} + \frac{18}{12} + \frac{10}{12} = \frac{9 + 18 + 10}{12} = \frac{37}{12}
\]
So, you would add the weights of the lettuce, tomatoes, and cheese together to find the total weight of the salad. The operation used would be addition.