Question

Given the formula for the volume of a box, V=lwh
𝑉
=
𝑙
𝑤
ℎ
, which equation best represents the remaining units when justifying your rearrangement to solve for the width?(1 point)
Responses

in.=in.
in.
=
in.
in. equals in.

in.3in.2=in.
in.
3
in.
2
=
in.
Start Fraction in. cubed over in. squared End Fraction equals in.

in.3in.2=in.3in.2
in.
3
in.
2
=
in.
3
in.
2
Start Fraction in. cubed over in. squared End Fraction equals Start Fraction in. cubed over in. squared End Fraction

in.3=in.3

Answer 1

To solve for the width \( w \) in the volume formula \( V = lwh \), you can rearrange the equation as follows:

1. Start with the original formula:
\[
V = lwh
\]

2. To isolate \( w \), divide both sides by \( lh \):
\[
w = \frac{V}{lh}
\]

When justifying this rearrangement in terms of units, we need to express the volume \( V \) in cubic inches (in³) and the dimensions \( l \) and \( h \) in inches (in).

The relevant units when you perform the operation (dividing volume by the product of length and height) will be:

- The volume \( V \) has units of in³,
- The product \( lh \) has units of in² (since both \( l \) and \( h \) are in inches).

Dividing in³ by in² results in units of in (inches).

Thus, the appropriate justification for the rearrangement to solve for the width \( w \) includes a representation of units that shows:

\[
\frac{\text{in}^3}{\text{in}^2} = \text{in}
\]

Therefore, the best response that captures this relationship is:

**Start Fraction in. cubed over in. squared End Fraction equals in.**