Let \( p \) be the per-minute cost of parking.
On Monday, Zack parked for 68 minutes. The cost of parking that day is: \[ 68p \] He spent $34 shopping, so his total expenditure on Monday is: \[ 68p + 34 \]
On Thursday, Zack parked for 143 minutes. The cost of parking that day is: \[ 143p \] He spent $31 shopping, so his total expenditure on Thursday is: \[ 143p + 31 \]
According to the problem, Zack spent the same total amount on parking and shopping each day, which gives us the equation: \[ 68p + 34 = 143p + 31 \]
Now, we will solve this equation for \( p \).
First, we can rearrange the equation: \[ 68p + 34 - 31 = 143p \] This simplifies to: \[ 68p + 3 = 143p \]
Next, we will isolate \( p \) by subtracting \( 68p \) from both sides: \[ 3 = 143p - 68p \] This simplifies to: \[ 3 = 75p \]
Now, we can solve for \( p \) by dividing both sides by 75: \[ p = \frac{3}{75} = \frac{1}{25} \]
Thus, the per-minute cost of parking at the mall is: \[ \boxed{0.04} \]
This means the cost is $0.04 per minute.