Asked by random child who needs alot of help
Which situation could NOT represent a proportional relationship?
Responses
A The weight of the soccer team’s cooler is given by w = 0.5s + 5, where w is the weight of the cooler and s is the number of sports drinks in the cooler.
B The cost for tutoring is given by c = 20h, where c is the cost in dollars and h is the number of hours of tutoring.
C The value of US dollars to Mexican pesos is given by d = 18.73p, where d is the number of dollars and p is the number of pesos
D The value of feet to inches is given by i = 12f, where i is the number of inches and f is the number of feet.
Responses
A The weight of the soccer team’s cooler is given by w = 0.5s + 5, where w is the weight of the cooler and s is the number of sports drinks in the cooler.
B The cost for tutoring is given by c = 20h, where c is the cost in dollars and h is the number of hours of tutoring.
C The value of US dollars to Mexican pesos is given by d = 18.73p, where d is the number of dollars and p is the number of pesos
D The value of feet to inches is given by i = 12f, where i is the number of inches and f is the number of feet.
Answers
Answered by
GPT-4o mini
To determine which situation does not represent a proportional relationship, we need to identify if the relationships are linear and start from the origin (0,0). A proportional relationship can be described by the equation \( y = kx \), where \( k \) is a constant.
Let's evaluate each option:
A. \( w = 0.5s + 5 \)
This equation has a y-intercept of 5, meaning when \( s = 0 \), \( w \) does not equal 0 (it equals 5). This indicates that the relationship is **not proportional**.
B. \( c = 20h \)
This equation has no constant term added; it passes through the origin (0,0). This indicates a proportional relationship.
C. \( d = 18.73p \)
This equation also has no constant term added and passes through the origin (0,0), indicating a proportional relationship.
D. \( i = 12f \)
This equation also has no constant term, so it passes through the origin (0,0), indicating a proportional relationship.
Therefore, the situation that could NOT represent a proportional relationship is:
**A**: The weight of the soccer team’s cooler is given by \( w = 0.5s + 5 \).
Let's evaluate each option:
A. \( w = 0.5s + 5 \)
This equation has a y-intercept of 5, meaning when \( s = 0 \), \( w \) does not equal 0 (it equals 5). This indicates that the relationship is **not proportional**.
B. \( c = 20h \)
This equation has no constant term added; it passes through the origin (0,0). This indicates a proportional relationship.
C. \( d = 18.73p \)
This equation also has no constant term added and passes through the origin (0,0), indicating a proportional relationship.
D. \( i = 12f \)
This equation also has no constant term, so it passes through the origin (0,0), indicating a proportional relationship.
Therefore, the situation that could NOT represent a proportional relationship is:
**A**: The weight of the soccer team’s cooler is given by \( w = 0.5s + 5 \).