It takes 1 molecule of nitrogen and 3

Question

molecules of hydrogen to produce 2
molecules of ammonia using the following formula:

1N2+ 3H2 → 2NH3

Identify which combination of molecules will produce ammonia with no leftovers?

(1 point)
Responses

8N2
and 4H2
8 n sub 2 and 4 h sub 2

4N2
and 4H2
4 n sub 2 and 4 h sub 2

2N2
and 6H2
2 n sub 2 and 6 h sub 2

5N2
and 6H2

Answer 1

To determine which combination of molecules will produce ammonia with no leftovers, we need to examine how the stoichiometry of the reaction works based on the balanced equation:

\[ 1 \text{N}_2 + 3 \text{H}_2 \rightarrow 2 \text{NH}_3 \]

This means:

• 1 molecule of nitrogen is required to produce 2 molecules of ammonia.
• 3 molecules of hydrogen are required to produce 2 molecules of ammonia.

From the equation, we see that for every 1 molecule of \(N_2\), we need 3 molecules of \(H_2\).

Now, let's analyze each option:

1. 8 N2 and 4 H2:

   • Nitrogen can produce: \(8 \times 2 = 16\) NH3, which needs \(16 \times 1.5 = 24\) H2 (since 3 H2 are required for every 2 NH3). There are not enough H2 here.

2. 4 N2 and 4 H2:

   • Nitrogen can produce: \(4 \times 2 = 8\) NH3, which needs \(8 \times 1.5 = 12\) H2. There are not enough H2 here.

3. 2 N2 and 6 H2:

   • Nitrogen can produce: \(2 \times 2 = 4\) NH3, which needs \(4 \times 1.5 = 6\) H2. This combination works perfectly since it matches the hydrogen needed.

4. 5 N2 and 6 H2:

   • Nitrogen can produce: \(5 \times 2 = 10\) NH3, which needs \(10 \times 1.5 = 15\) H2. There are not enough H2 here.

The only option that produces ammonia with no leftovers is 2 N2 and 6 H2.