Find (f g)(x) when f(x) =x*+8x+15 and g(x) =

x-9'
(1 point)
5x +25
(f•g) (x) =
オー3
(f g) (x)=
x*+16x+94x7+240x+216
5x + 25
(f•g) (x)=
x+3
25
40
(f.g) (x)=
x* - 18x7+81
+スマータ
- +15

1 answer

To find \((f \cdot g)(x)\) (which means \(f(x) \cdot g(x)\)), we need to multiply the functions \(f(x)\) and \(g(x)\) together.

You provided:

  • \(f(x) = x^2 + 8x + 15\)
  • \(g(x) = x - 9\)

Now we will multiply these two expressions:

\[ (f \cdot g)(x) = (x^2 + 8x + 15)(x - 9) \]

Using the distributive property (also known as the FOIL method for binomials), we can expand this expression:

  1. Multiply \(x^2\) by both terms in \(g(x)\): \[ x^2 \cdot x = x^3 \] \[ x^2 \cdot (-9) = -9x^2 \]

  2. Multiply \(8x\) by both terms in \(g(x)\): \[ 8x \cdot x = 8x^2 \] \[ 8x \cdot (-9) = -72x \]

  3. Multiply \(15\) by both terms in \(g(x)\): \[ 15 \cdot x = 15x \] \[ 15 \cdot (-9) = -135 \]

Now, combine all these terms together: \[ x^3 + (-9x^2 + 8x^2) + (-72x + 15x) - 135 \]

Simplifying the coefficients: \[ x^3 + (-1x^2) + (-57x) - 135 \]

So we have: \[ (f \cdot g)(x) = x^3 - x^2 - 57x - 135 \]

Therefore, the final answer for \((f \cdot g)(x)\) is: \[ \boxed{x^3 - x^2 - 57x - 135} \]