Question

The age of four brothers on the consecutive integers with some of 130. How old are the brothers?
N + __ + __+ __+ = 130

Answer 1

Let's denote the ages of the four brothers as \( N, N+1, N+2, N+3 \), where \( N \) is the age of the youngest brother. The sum of their ages can be set up as follows:

\[
N + (N+1) + (N+2) + (N+3) = 130
\]

Now, let's simplify the left side:

\[
N + N + 1 + N + 2 + N + 3 = 130
\]
\[
4N + 6 = 130
\]

Next, we isolate \( N \):

\[
4N = 130 - 6
\]
\[
4N = 124
\]
\[
N = 31
\]

Now we can find the ages of the four brothers:

- The youngest brother is \( N = 31 \).
- The second brother is \( N+1 = 32 \).
- The third brother is \( N+2 = 33 \).
- The oldest brother is \( N+3 = 34 \).

Therefore, the ages of the four brothers are **31, 32, 33, and 34**.