plane is flying at 600km/h and reduces its velocity uniformly to 70km/h in 3 mins. what is its acceleration

1 answer

To find the acceleration of the plane, we can use the formula for acceleration, which is given by:

\[ a = \frac{\Delta v}{\Delta t} \]

where:

  • \( a \) is the acceleration,
  • \( \Delta v \) is the change in velocity,
  • \( \Delta t \) is the change in time.
  1. Convert the time from minutes to hours: \( 3 \) minutes = \( \frac{3}{60} \) hours = \( 0.05 \) hours

  2. Initial velocity (\( v_i \)): \( 600 \) km/h

  3. Final velocity (\( v_f \)): \( 70 \) km/h

  4. Calculate the change in velocity (\( \Delta v \)): \[ \Delta v = v_f - v_i = 70 , \text{km/h} - 600 , \text{km/h} = -530 , \text{km/h} \]

  5. Calculate the acceleration (\( a \)): \[ a = \frac{\Delta v}{\Delta t} = \frac{-530 , \text{km/h}}{0.05 , \text{h}} = -10600 , \text{km/h}^2 \]

So, the acceleration of the plane is \(-10600 , \text{km/h}^2\). This negative sign indicates a reduction in speed, confirming that it is deceleration.