Question

The first week at Javier's new job he spent $12.48, $9.50, $10.25, $4.99, and $8.59 on lunch.

In the second week, he spent $3 more in total for the 5 lunches than the first week.

What is the increase in the mean for the second week compared to the first?



Round the answer to the nearest penny.

Enter your answer in the box.

Answer 1

First, we need to calculate the total spending for Javier's lunches in the first week.

The amounts he spent are:
- $12.48
- $9.50
- $10.25
- $4.99
- $8.59

Let's add these amounts together:

\[
12.48 + 9.50 + 10.25 + 4.99 + 8.59 = 55.81
\]

So, the total spending for the first week is $55.81.

Next, we calculate the mean spending for the first week. Since there were 5 lunches, we divide the total by 5:

\[
\text{Mean for Week 1} = \frac{55.81}{5} = 11.162
\]

Now, let's round this to the nearest penny:

\[
\text{Mean for Week 1} \approx 11.16
\]

In the second week, it is given that he spent $3 more than in the first week, so the total spending for the second week is:

\[
55.81 + 3 = 58.81
\]

Now we calculate the mean spending for the second week:

\[
\text{Mean for Week 2} = \frac{58.81}{5} = 11.762
\]

Rounding this to the nearest penny:

\[
\text{Mean for Week 2} \approx 11.76
\]

Finally, we find the increase in mean spending from the first week to the second week:

\[
\text{Increase in Mean} = 11.76 - 11.16 = 0.60
\]

Thus, the increase in the mean for the second week compared to the first is:

\[
\boxed{0.60}
\]