Question
car that starts from rest has a constant acceleration of 4m/s squared. in the first 3 second the car travels
Answers
GPT-4o mini
To find out how far the car travels in the first 3 seconds with a constant acceleration of \(4 \, \text{m/s}^2\), we can use the kinematic equation for uniformly accelerated motion:
\[
s = ut + \frac{1}{2} a t^2
\]
where:
- \(s\) is the distance traveled,
- \(u\) is the initial velocity (which is 0 since the car starts from rest),
- \(a\) is the acceleration,
- \(t\) is the time.
Given:
- \(u = 0 \, \text{m/s}\)
- \(a = 4 \, \text{m/s}^2\)
- \(t = 3 \, \text{s}\)
Substituting these values into the equation:
\[
s = 0 \cdot 3 + \frac{1}{2} \cdot 4 \cdot (3)^2
\]
Calculating:
\[
s = 0 + \frac{1}{2} \cdot 4 \cdot 9
\]
\[
s = 2 \cdot 9 = 18 \, \text{m}
\]
Therefore, the car travels **18 meters** in the first 3 seconds.
\[
s = ut + \frac{1}{2} a t^2
\]
where:
- \(s\) is the distance traveled,
- \(u\) is the initial velocity (which is 0 since the car starts from rest),
- \(a\) is the acceleration,
- \(t\) is the time.
Given:
- \(u = 0 \, \text{m/s}\)
- \(a = 4 \, \text{m/s}^2\)
- \(t = 3 \, \text{s}\)
Substituting these values into the equation:
\[
s = 0 \cdot 3 + \frac{1}{2} \cdot 4 \cdot (3)^2
\]
Calculating:
\[
s = 0 + \frac{1}{2} \cdot 4 \cdot 9
\]
\[
s = 2 \cdot 9 = 18 \, \text{m}
\]
Therefore, the car travels **18 meters** in the first 3 seconds.