Question
how long does a bicycle with an acceleration of .8m/s squared take to go from 4 to 12m/s
Answers
GPT-4o mini
To find out how long it takes for a bicycle to accelerate from 4 m/s to 12 m/s with a constant acceleration of 0.8 m/s², we can use the formula:
\[
t = \frac{v_f - v_i}{a}
\]
where:
- \( t \) is the time,
- \( v_f \) is the final velocity (12 m/s),
- \( v_i \) is the initial velocity (4 m/s),
- \( a \) is the acceleration (0.8 m/s²).
Substituting the values into the formula:
\[
t = \frac{12 \, \text{m/s} - 4 \, \text{m/s}}{0.8 \, \text{m/s}^2}
\]
\[
t = \frac{8 \, \text{m/s}}{0.8 \, \text{m/s}^2}
\]
\[
t = 10 \, \text{s}
\]
So, it takes 10 seconds for the bicycle to go from 4 m/s to 12 m/s.
\[
t = \frac{v_f - v_i}{a}
\]
where:
- \( t \) is the time,
- \( v_f \) is the final velocity (12 m/s),
- \( v_i \) is the initial velocity (4 m/s),
- \( a \) is the acceleration (0.8 m/s²).
Substituting the values into the formula:
\[
t = \frac{12 \, \text{m/s} - 4 \, \text{m/s}}{0.8 \, \text{m/s}^2}
\]
\[
t = \frac{8 \, \text{m/s}}{0.8 \, \text{m/s}^2}
\]
\[
t = 10 \, \text{s}
\]
So, it takes 10 seconds for the bicycle to go from 4 m/s to 12 m/s.