6(-3v + 1)= 5 (-2v-2)

1 answer

Let's solve the equation step by step:

Given the equation:

\[ 6(-3v + 1) = 5(-2v - 2) \]

First, distribute the 6 on the left side and the 5 on the right side:

\[ 6 \times -3v + 6 \times 1 = 5 \times -2v + 5 \times -2 \]

This simplifies to:

\[ -18v + 6 = -10v - 10 \]

Next, let's move all terms involving \( v \) to one side and constant terms to the other side. We can add \( 18v \) to both sides:

\[ 6 = -10v + 18v - 10 \]

This simplifies to:

\[ 6 = 8v - 10 \]

Now, add 10 to both sides:

\[ 6 + 10 = 8v \]

This simplifies to:

\[ 16 = 8v \]

Now, divide both sides by 8:

\[ v = \frac{16}{8} = 2 \]

Thus, the solution is:

\[ \boxed{2} \]