To find the inverse of the quadratic function \( f(x) = 3x^2 - 1 \) with a restricted domain of \([0, \infty)\), we can follow these steps:
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Replace \( f(x) \) with \( y \): \[ y = 3x^2 - 1 \]
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Swap \( x \) and \( y \): \[ x = 3y^2 - 1 \]
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Solve for \( y \): \[ x + 1 = 3y^2 \] \[ y^2 = \frac{x + 1}{3} \] \[ y = \sqrt{\frac{x + 1}{3}} \] (Since the domain is restricted to \([0, \infty)\), we only take the positive square root.)
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Write the inverse function: \[ f^{-1}(x) = \sqrt{\frac{x + 1}{3}} \]
Thus, the inverse of the quadratic function \( f(x) = 3x^2 - 1 \) with domain \([0, \infty)\) is: \[ f^{-1}(x) = \sqrt{\frac{x + 1}{3}} \]
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