Question
A parasail is 1/20
of a kilometer above the water. Then, after 10 minutes, the parasail is 1/50
of a kilometer above the water. What is the difference in height?
of a kilometer above the water. Then, after 10 minutes, the parasail is 1/50
of a kilometer above the water. What is the difference in height?
Answers
GPT-4o mini
To find the difference in height between the two positions of the parasail, we can first convert the fractions of kilometers to a common measure.
The height of the parasail at the first position is:
\[
\text{Height}_1 = \frac{1}{20} \text{ km}
\]
The height of the parasail at the second position is:
\[
\text{Height}_2 = \frac{1}{50} \text{ km}
\]
Now, we need to find a common denominator to subtract these two fractions. The least common multiple of 20 and 50 is 100. We can convert each fraction to have this common denominator.
For \(\frac{1}{20}\):
\[
\frac{1}{20} = \frac{5}{100}
\]
For \(\frac{1}{50}\):
\[
\frac{1}{50} = \frac{2}{100}
\]
Now we can subtract the two heights:
\[
\text{Difference in height} = \text{Height}_1 - \text{Height}_2 = \frac{5}{100} - \frac{2}{100} = \frac{3}{100} \text{ km}
\]
Converting \(\frac{3}{100}\) kilometers to meters (since \(1\) km = \(1000\) m):
\[
\frac{3}{100} \text{ km} = \frac{3}{100} \times 1000 \text{ m} = 30 \text{ m}
\]
Therefore, the difference in height is:
\[
\boxed{30 \text{ m}}
\]
The height of the parasail at the first position is:
\[
\text{Height}_1 = \frac{1}{20} \text{ km}
\]
The height of the parasail at the second position is:
\[
\text{Height}_2 = \frac{1}{50} \text{ km}
\]
Now, we need to find a common denominator to subtract these two fractions. The least common multiple of 20 and 50 is 100. We can convert each fraction to have this common denominator.
For \(\frac{1}{20}\):
\[
\frac{1}{20} = \frac{5}{100}
\]
For \(\frac{1}{50}\):
\[
\frac{1}{50} = \frac{2}{100}
\]
Now we can subtract the two heights:
\[
\text{Difference in height} = \text{Height}_1 - \text{Height}_2 = \frac{5}{100} - \frac{2}{100} = \frac{3}{100} \text{ km}
\]
Converting \(\frac{3}{100}\) kilometers to meters (since \(1\) km = \(1000\) m):
\[
\frac{3}{100} \text{ km} = \frac{3}{100} \times 1000 \text{ m} = 30 \text{ m}
\]
Therefore, the difference in height is:
\[
\boxed{30 \text{ m}}
\]