To solve \( 1 \frac{2}{6} + 6 \frac{3}{6} \), we first convert the mixed numbers into improper fractions.
-
Convert \( 1 \frac{2}{6} \): \[ 1 \frac{2}{6} = \frac{1 \times 6 + 2}{6} = \frac{6 + 2}{6} = \frac{8}{6} \]
-
Convert \( 6 \frac{3}{6} \): \[ 6 \frac{3}{6} = \frac{6 \times 6 + 3}{6} = \frac{36 + 3}{6} = \frac{39}{6} \]
Now, we add the two improper fractions: \[ \frac{8}{6} + \frac{39}{6} = \frac{8 + 39}{6} = \frac{47}{6} \]
Next, we convert \( \frac{47}{6} \) back into a mixed number. We do this by dividing 47 by 6: \[ 47 \div 6 = 7 \quad \text{(whole number)}, \quad \text{with a remainder of } 5 \]
Thus, we have: \[ \frac{47}{6} = 7 \frac{5}{6} \]
So, the final result is: \[ \boxed{7 \frac{5}{6}} \]