Question

Given the formula for the volume of a box, V=lwh
, which equation best represents the remaining units when justifying your rearrangement to solve for the width?(1 point)
Responses

in.=in.
in. equals in.

in.3in.2=in.3in.2
Start Fraction in. cubed over in. squared End Fraction equals Start Fraction in. cubed over in. squared End Fraction

in.3in.2=in.
Start Fraction in. cubed over in. squared End Fraction equals in.

in.3=in.3

Answer 1

To solve for the width \( w \) in the formula for the volume of a box \( V = lwh \), we can rearrange it as follows:

1. Start with \( V = lwh \).
2. To isolate \( w \), we divide both sides by \( lh \):
\[
w = \frac{V}{lh}
\]

When considering the units involved, we analyze the volume \( V \) which is in cubic inches (in³), and the product \( lh \) which is in square inches (in²).

The appropriate unit analysis shows:
\[
\frac{\text{in}^3}{\text{in}^2} = \text{in}
\]

Thus, the equation that best represents the remaining units after rearranging to solve for width is:

**Start Fraction in. cubed over in. squared End Fraction equals in.**

So the correct response is:
**Start Fraction in. cubed over in. squared End Fraction equals in.**