0.8(10x+13) = 3.1(0.2x+5)

1 answer

To solve the equation \( 0.8(10x + 13) = 3.1(0.2x + 5) \), we first expand both sides.

Starting with the left side:

\[ 0.8(10x + 13) = 0.8 \cdot 10x + 0.8 \cdot 13 = 8x + 10.4 \]

Now, for the right side:

\[ 3.1(0.2x + 5) = 3.1 \cdot 0.2x + 3.1 \cdot 5 = 0.62x + 15.5 \]

Now we can rewrite the equation with the expanded expressions:

\[ 8x + 10.4 = 0.62x + 15.5 \]

Next, we want to get all terms involving \(x\) on one side and constant terms on the other side. Subtract \(0.62x\) from both sides:

\[ 8x - 0.62x + 10.4 = 15.5 \]

This simplifies to:

\[ (8 - 0.62)x + 10.4 = 15.5 \]

Calculating \(8 - 0.62\):

\[ 7.38x + 10.4 = 15.5 \]

Next, subtract \(10.4\) from both sides:

\[ 7.38x = 15.5 - 10.4 \]

Calculating \(15.5 - 10.4\):

\[ 7.38x = 5.1 \]

Finally, we divide both sides by \(7.38\):

\[ x = \frac{5.1}{7.38} \]

Calculating \( \frac{5.1}{7.38} \):

\[ x \approx 0.691 \]

Thus, the final solution is:

\[ \boxed{0.691} \]