Asked by random child who needs alot of help
Solve the following inequality for x
ax+5 is greater than 13
Responses
A
x is greater than 8 minus A
B
x is less than 8 over A
C
x is greater than A over 8
D
ax+5 is greater than 13
Responses
A
x is greater than 8 minus A
B
x is less than 8 over A
C
x is greater than A over 8
D
Answers
Answered by
GPT-4o mini
To solve the inequality \( ax + 5 > 13 \), we first isolate \( x \).
1. Subtract 5 from both sides:
\[
ax > 13 - 5
\]
\[
ax > 8
\]
2. Divide both sides by \( a \) (note: if \( a \) is negative, the direction of the inequality changes):
\[
x > \frac{8}{a} \quad \text{(if \( a > 0 \))}
\]
\[
x < \frac{8}{a} \quad \text{(if \( a < 0 \))}
\]
Assuming \( a > 0 \), the solution is:
\[
x > \frac{8}{a}
\]
So, the correct response from the options given would be:
**C**: \( x \) is greater than \( \frac{A}{8} \) (Note: "A" here is used for clarity; it should represent \( a \)). If \( a < 0 \) is considered, the inequality would flip.
However, clarify what "A" represents in your context, and adjust accordingly. The interpretation helps determine the choice correctly based on the sign of \( a \).
1. Subtract 5 from both sides:
\[
ax > 13 - 5
\]
\[
ax > 8
\]
2. Divide both sides by \( a \) (note: if \( a \) is negative, the direction of the inequality changes):
\[
x > \frac{8}{a} \quad \text{(if \( a > 0 \))}
\]
\[
x < \frac{8}{a} \quad \text{(if \( a < 0 \))}
\]
Assuming \( a > 0 \), the solution is:
\[
x > \frac{8}{a}
\]
So, the correct response from the options given would be:
**C**: \( x \) is greater than \( \frac{A}{8} \) (Note: "A" here is used for clarity; it should represent \( a \)). If \( a < 0 \) is considered, the inequality would flip.
However, clarify what "A" represents in your context, and adjust accordingly. The interpretation helps determine the choice correctly based on the sign of \( a \).
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