Question

Find the midpoint of M, of AB.
A=(-2, -10) B=(-6,0).

Answer 1

To find the midpoint \( M \) of the line segment \( AB \) with points \( A(-2, -10) \) and \( B(-6, 0) \), you can use the midpoint formula:

\[
M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)
\]

Here, \( (x_1, y_1) \) are the coordinates of point \( A \) and \( (x_2, y_2) \) are the coordinates of point \( B \).

Now, substituting the values:

- For point \( A \), \( x_1 = -2 \) and \( y_1 = -10 \)
- For point \( B \), \( x_2 = -6 \) and \( y_2 = 0 \)

Now calculate the x-coordinate of the midpoint:

\[
x_M = \frac{-2 + (-6)}{2} = \frac{-2 - 6}{2} = \frac{-8}{2} = -4
\]

Next, calculate the y-coordinate of the midpoint:

\[
y_M = \frac{-10 + 0}{2} = \frac{-10}{2} = -5
\]

Thus, the coordinates of the midpoint \( M \) are:

\[
M = (-4, -5)
\]

Therefore, the midpoint of \( AB \) is \( \boxed{(-4, -5)} \).