Rubidium has an atomic number of 37 and a mass number of 85. How many protons, neutrons, and electrons does an ion of rubidium with a 1+ charge have?(1 point)

Question

Responses

37 protons, 48 neutrons, and 38 electrons
37 protons, 48 neutrons, and 38 electrons

37 protons, 48 neutrons, and 36 electrons
37 protons, 48 neutrons, and 36 electrons

48 protons, 37 neutrons, and 36 electrons
48 protons, 37 neutrons, and 36 electrons

48 protons, 37 neutrons, and 38 electrons

Answer 1

To determine the number of protons, neutrons, and electrons in an ion of rubidium (Rb) with a 1+ charge, we can follow these steps:

1. Identify the number of protons: The atomic number of rubidium is 37, which means it has 37 protons.

2. Calculate the number of neutrons: The mass number of rubidium is 85. The number of neutrons can be found by subtracting the number of protons from the mass number: \[ \text{Number of neutrons} = \text{Mass number} - \text{Number of protons} = 85 - 37 = 48 \] Therefore, rubidium has 48 neutrons.

3. Determine the number of electrons: A neutral atom has an equal number of electrons and protons. However, a 1+ charged ion indicates that it has lost one electron. Thus, the number of electrons will be: \[ \text{Number of electrons} = \text{Number of protons} - 1 = 37 - 1 = 36 \]

Putting it all together:

• Protons: 37
• Neutrons: 48
• Electrons: 36

Thus, the correct answer is: 37 protons, 48 neutrons, and 36 electrons.