What is the inverse of the function f(x) = x + 2? h(x) = 18x – 2 h(x) = 9x – 18 h(x) = 9x + 18 h(x) = 18x + 2

1 answer

To find the inverse of the function \( f(x) = x + 2 \), we start by setting \( y = f(x) \):

\[ y = x + 2 \]

Next, we solve for \( x \) in terms of \( y \):

\[ x = y - 2 \]

Now we exchange \( x \) and \( y \) to find the inverse function:

\[ f^{-1}(x) = x - 2 \]

Now, we can compare this result with the given options for \( h(x) \):

  1. \( h(x) = 18x - 2 \)
  2. \( h(x) = 9x - 18 \)
  3. \( h(x) = 9x + 18 \)
  4. \( h(x) = 18x + 2 \)

None of these functions appear to directly correspond to the inverse function \( f^{-1}(x) = x - 2 \).

Thus, none of the options provided represent the inverse of the function \( f(x) = x + 2 \).