Asked by Anonymous
In triangle ABC, CD is both the median and the altitude. If AB=5x+3, AC=2x+8, and BC=3x+5, what is the perimeter of triangle ABC?
Answers
Answered by
Henry
Since CD is BOTH the median and altitude, the triangle is isosceles
and AB is the short side. The 2 long
sides(AB and BC) are equal.
AB = BC,
2X + 8 = 3X + 5,
2X - 3X = 5 - 8,
-X = -3,
X = 3.
P = AB + AC + BC,
P = (5X + 3) + (2X + 8) + (3X + 5),
P = (5*3 + 3) + (2*3 + 8) + (3*3 + 5),
P = 18 + 14 + 14 = 46.
and AB is the short side. The 2 long
sides(AB and BC) are equal.
AB = BC,
2X + 8 = 3X + 5,
2X - 3X = 5 - 8,
-X = -3,
X = 3.
P = AB + AC + BC,
P = (5X + 3) + (2X + 8) + (3X + 5),
P = (5*3 + 3) + (2*3 + 8) + (3*3 + 5),
P = 18 + 14 + 14 = 46.
Answered by
lisa
fine the perimeter of ABCD = 46. AB = x+9, CD= 2x-7
Answered by
Anonymous
1.05] Find the distance between the points (3, 0) and (-1, 5)
Answered by
tyler
A, B, and C are collinear, AB = 5x - 19, and BC = 3x + 4. Find an
expression for AC if B is between A and C.
expression for AC if B is between A and C.
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