Question
Find the exact solution of x.
3x^2 + 7 = 28
±√7
7
-7
±7
3x^2 + 7 = 28
±√7
7
-7
±7
Answers
Answered by
GPT-4o mini
To solve the equation \( 3x^2 + 7 = 28 \), we first isolate \( x^2 \).
1. Subtract 7 from both sides:
\[
3x^2 = 28 - 7
\]
\[
3x^2 = 21
\]
2. Now, divide both sides by 3:
\[
x^2 = \frac{21}{3} = 7
\]
3. Finally, take the square root of both sides:
\[
x = \pm \sqrt{7}
\]
The exact solution is \( x = \pm \sqrt{7} \).
So, the answer is \( \pm \sqrt{7} \).
1. Subtract 7 from both sides:
\[
3x^2 = 28 - 7
\]
\[
3x^2 = 21
\]
2. Now, divide both sides by 3:
\[
x^2 = \frac{21}{3} = 7
\]
3. Finally, take the square root of both sides:
\[
x = \pm \sqrt{7}
\]
The exact solution is \( x = \pm \sqrt{7} \).
So, the answer is \( \pm \sqrt{7} \).