To solve the equation \( 3x^2 + 7 = 28 \), we first isolate \( x^2 \).
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Subtract 7 from both sides: \[ 3x^2 = 28 - 7 \] \[ 3x^2 = 21 \]
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Now, divide both sides by 3: \[ x^2 = \frac{21}{3} = 7 \]
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Finally, take the square root of both sides: \[ x = \pm \sqrt{7} \]
The exact solution is \( x = \pm \sqrt{7} \).
So, the answer is \( \pm \sqrt{7} \).