If the torque required to loosen a nut on the wheel of a car has a magnitude of 40.1 N*m, what minimum force must be exerted by a mechanic at the end of a 38.2 cm wrench to loosen the nut?

torque=force*arm=40.1*.382 N-m

It should be 40.1/.382

If the torque required to loosen a nut on the wheel of a car has a magnitude of 40.0 N-m, what

minimum force must be exerted by a mechanic at the end of a 0.30-m wrench to loosen the
nut?

To solve this problem, we need to use the formula for torque: Torque = Force * Lever arm.

In this case, the torque required to loosen the nut is given as 40.1 N*m.
The lever arm is the distance between the nut and the point at which the force is applied, which is 38.2 cm (or 0.382 m).

Now, we can rearrange the formula to solve for force:
Force = Torque / Lever arm

Plugging in the given values:
Force = 40.1 N*m / 0.382 m

Now, dividing 40.1 N*m by 0.382 m gives us the minimum force required to loosen the nut. So, using a calculator, we find:

Force ≈ 104.7 N

Therefore, the minimum force that must be exerted by a mechanic at the end of a 38.2 cm wrench to loosen the nut is approximately 104.7 Newtons.