Asked by Anonymous

Find the average value of sqrt(cosx)on the interval [-1,1]
Answered by bobpursley
Integrate it, then divide by 2. I will be happy to critique your thinking.
Answered by Anonymous
Here is what I get when I integrate it:[(2/3)(cosx)^(3/2)(-sinx)]
Now I plug the interval into it:
(1/2)[[(2/3)(cos1)^(3/2)(-sin1)]-[(2/3)(cos(-1))^(3/2)(-sin(-1))]]
I did something wrong, since the answer is suppose to be .914
Answered by bobpursley
If you differentiate what you got for the integral, you should get sqrt(cosx). I didn't get that. You may want to do some numerical integration, your calculator should be able to do that. Or you can do it with Simpson's method.
Answered by Anonymous
I haven't learned about the Simpson's method.
Answered by Anonymous101
What type of calculator do u currently have?
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