Question
The equation for a base solution is B + H2O ⇌ BH+ + OH−
. The strength of the base in a solution is increased. How will the number of particles change?(1 point)
Responses
The number of BH+superscript molecules will increase, and the number of water molecules will decrease.
The number of B H + superscript molecules will increase, and the number of water molecules will decrease.
The number of B molecules will increase, and the number of water molecules will decrease.
The number of B molecules will increase, and the number of water molecules will decrease.
The number of OH–minus ions will increase, and the number of BH+superscript molecules will decrease.
The number of OH – minus ions will increase, and the number of B H + superscript molecules will decrease.
The number of B molecules will increase, and the number of OH–minus ions will decrease.
. The strength of the base in a solution is increased. How will the number of particles change?(1 point)
Responses
The number of BH+superscript molecules will increase, and the number of water molecules will decrease.
The number of B H + superscript molecules will increase, and the number of water molecules will decrease.
The number of B molecules will increase, and the number of water molecules will decrease.
The number of B molecules will increase, and the number of water molecules will decrease.
The number of OH–minus ions will increase, and the number of BH+superscript molecules will decrease.
The number of OH – minus ions will increase, and the number of B H + superscript molecules will decrease.
The number of B molecules will increase, and the number of OH–minus ions will decrease.
Answers
Answered by
GPT-4o mini
In the equilibrium represented by the equation:
\[ B + H_2O \rightleftharpoons BH^+ + OH^- \]
when the strength of the base \( B \) in a solution is increased, more \( B \) will react with water to form \( BH^+ \) and \( OH^- \). This increase in base concentration will drive the reaction to the right, according to Le Chatelier's principle.
As a result, the number of \( BH^+ \) ions will increase, and the number of \( OH^- \) ions will also increase, while the amount of water (\( H_2O \)) will remain relatively unchanged because it is the solvent.
Therefore, the correct response from the provided options is:
**The number of BH\(^+\) molecules will increase, and the number of OH\(^-\) ions will increase.**
However, since this specific option is not listed accurately in your responses, the most relevant description would be:
**The number of BH\(^+\) molecules will increase, and the number of water molecules will decrease.**
But note, normally the water quantity doesn't significantly decrease as it acts primarily as a solvent. The implication is that the concentration of \( BH^+ \) and \( OH^- \) increases, which reflects an increased base strength.
If you're seeking an option that was provided accurately concerning the increase in \( OH^-\), consider:
**The number of OH\(^-\) ions will increase, and the number of BH\(^+\) molecules will increase.**
Just clarify that the water does not significantly decrease.
\[ B + H_2O \rightleftharpoons BH^+ + OH^- \]
when the strength of the base \( B \) in a solution is increased, more \( B \) will react with water to form \( BH^+ \) and \( OH^- \). This increase in base concentration will drive the reaction to the right, according to Le Chatelier's principle.
As a result, the number of \( BH^+ \) ions will increase, and the number of \( OH^- \) ions will also increase, while the amount of water (\( H_2O \)) will remain relatively unchanged because it is the solvent.
Therefore, the correct response from the provided options is:
**The number of BH\(^+\) molecules will increase, and the number of OH\(^-\) ions will increase.**
However, since this specific option is not listed accurately in your responses, the most relevant description would be:
**The number of BH\(^+\) molecules will increase, and the number of water molecules will decrease.**
But note, normally the water quantity doesn't significantly decrease as it acts primarily as a solvent. The implication is that the concentration of \( BH^+ \) and \( OH^- \) increases, which reflects an increased base strength.
If you're seeking an option that was provided accurately concerning the increase in \( OH^-\), consider:
**The number of OH\(^-\) ions will increase, and the number of BH\(^+\) molecules will increase.**
Just clarify that the water does not significantly decrease.