To solve the equation \(2 |2y - 6| - 3 = 3\), we first isolate the absolute value expression.
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Add 3 to both sides: \[ 2 |2y - 6| = 6 \]
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Divide both sides by 2: \[ |2y - 6| = 3 \]
Now we can solve for \(y\) by considering the definition of absolute value. This gives us two cases to solve:
Case 1: \[ 2y - 6 = 3 \] Add 6 to both sides: \[ 2y = 9 \] Divide by 2: \[ y = \frac{9}{2} \]
Case 2: \[ 2y - 6 = -3 \] Add 6 to both sides: \[ 2y = 3 \] Divide by 2: \[ y = \frac{3}{2} \]
So, the solutions to the equation \(2 |2y - 6| - 3 = 3\) are:
\[ y = \frac{9}{2}, \frac{3}{2} \]
Thus, the correct choice is: A. \[ y = \frac{9}{2}, \frac{3}{2} \]