Asked by Jessica
Put in simplest form:
16x^7y^12-10X^5y^8/2x^2y^9
16x^7y^12-10X^5y^8/2x^2y^9
Answers
Answered by
KELLY
16x^7y^12-10X^5y^8/2x^2y^9
=(16x^7y^12/2x^2y^9)-(10x^5y^8/2x^2y^9)
=((16/2)*x^(7-2)*y^(12-9))-((10/2)*x^(5-2)*y^(8-9))
=8x^5y^3-5x^3y^-1
or
=(8x^5y^3)-((5x^3)/y)
=(16x^7y^12/2x^2y^9)-(10x^5y^8/2x^2y^9)
=((16/2)*x^(7-2)*y^(12-9))-((10/2)*x^(5-2)*y^(8-9))
=8x^5y^3-5x^3y^-1
or
=(8x^5y^3)-((5x^3)/y)
Answered by
PsyDAG
To make problem clearer, you need to include parentheses.
Do you mean:
(16x^7y^12-10X^5y^8)/(2x^2y^9)
or
16x^7y^12-(10X^5y^8)/(2x^2y^9)?
Do you mean:
(16x^7y^12-10X^5y^8)/(2x^2y^9)
or
16x^7y^12-(10X^5y^8)/(2x^2y^9)?
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