To find the 16th term of the sequence defined by the formula \( a(n) = -6 + 3(n - 1) \), we need to substitute \( n = 16 \) into the formula.
Let's calculate it step by step:
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Substitute \( n = 16 \) into the formula: \[ a(16) = -6 + 3(16 - 1) \]
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Calculate \( 16 - 1 \): \[ 16 - 1 = 15 \]
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Substitute this back into the equation: \[ a(16) = -6 + 3 \times 15 \]
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Calculate \( 3 \times 15 \): \[ 3 \times 15 = 45 \]
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Substitute this back into the formula: \[ a(16) = -6 + 45 \]
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Finally, calculate \( -6 + 45 \): \[ -6 + 45 = 39 \]
Therefore, the 16th term in the sequence is \( \boxed{39} \).