Question

when dividing x^3 - 8 bby x - 2, what is the remainder

Answers

GPT-4o mini
To find the remainder when dividing \( x^3 - 8 \) by \( x - 2 \), we can use the Remainder Theorem. According to the theorem, the remainder of the polynomial \( f(x) \) when divided by \( x - c \) is \( f(c) \).

Here, \( f(x) = x^3 - 8 \) and we want to evaluate it at \( c = 2 \):

\[
f(2) = (2)^3 - 8 = 8 - 8 = 0
\]

Thus, the remainder when dividing \( x^3 - 8 \) by \( x - 2 \) is \( \boxed{0} \).

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