To solve \( 1 \frac{5}{12} + 1 \frac{25}{1} \), we can start by converting the mixed numbers to improper fractions:
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Convert \( 1 \frac{5}{12} \) to an improper fraction:
- \( 1 \frac{5}{12} = \frac{12 \cdot 1 + 5}{12} = \frac{12 + 5}{12} = \frac{17}{12} \).
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Convert \( 1 \frac{25}{1} \) to an improper fraction:
- \( 1 \frac{25}{1} = \frac{1 \cdot 1 + 25}{1} = \frac{1 + 25}{1} = \frac{26}{1} = 26 \).
Now we can add the two fractions:
\[ \frac{17}{12} + 26 \]
To add these, we can express 26 as a fraction with the same denominator:
\[ 26 = \frac{26 \cdot 12}{12} = \frac{312}{12} \]
Now add the two fractions together:
\[ \frac{17}{12} + \frac{312}{12} = \frac{17 + 312}{12} = \frac{329}{12} \]
Now, we can convert \( \frac{329}{12} \) back to a mixed number:
Divide \( 329 \) by \( 12 \):
- \( 329 \div 12 = 27 \) with a remainder of \( 5 \).
So, this is \( 27 \frac{5}{12} \).
Thus, the final result is:
\[ 1 \frac{5}{12} + 1 \frac{25}{1} = 27 \frac{5}{12} \]