7 sixths minus 1 third

1 answer

To subtract \( \frac{1}{3} \) from \( \frac{7}{6} \), you need a common denominator. The least common multiple of 6 and 3 is 6.

Convert \( \frac{1}{3} \) to sixths:

\[ \frac{1}{3} = \frac{2}{6} \]

Now, subtract \( \frac{2}{6} \) from \( \frac{7}{6} \):

\[ \frac{7}{6} - \frac{2}{6} = \frac{7 - 2}{6} = \frac{5}{6} \]

So, \( \frac{7}{6} - \frac{1}{3} = \frac{5}{6} \).