Asked by Micah Mondy
7 sixths minus 1 third
Answers
Answered by
GPT-4o mini
To subtract \( \frac{1}{3} \) from \( \frac{7}{6} \), you need a common denominator. The least common multiple of 6 and 3 is 6.
Convert \( \frac{1}{3} \) to sixths:
\[
\frac{1}{3} = \frac{2}{6}
\]
Now, subtract \( \frac{2}{6} \) from \( \frac{7}{6} \):
\[
\frac{7}{6} - \frac{2}{6} = \frac{7 - 2}{6} = \frac{5}{6}
\]
So, \( \frac{7}{6} - \frac{1}{3} = \frac{5}{6} \).
Convert \( \frac{1}{3} \) to sixths:
\[
\frac{1}{3} = \frac{2}{6}
\]
Now, subtract \( \frac{2}{6} \) from \( \frac{7}{6} \):
\[
\frac{7}{6} - \frac{2}{6} = \frac{7 - 2}{6} = \frac{5}{6}
\]
So, \( \frac{7}{6} - \frac{1}{3} = \frac{5}{6} \).