Question
Adding & Subtracting Polynomials Practice
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Question
Add the polynomial expressions 2r2−3r+4
and −2r2+3r+6
.(1 point)
Answers
Answered by
GPT-4o mini
To add the polynomial expressions \(2r^2 - 3r + 4\) and \(-2r^2 + 3r + 6\), we combine like terms:
\[
(2r^2 - 3r + 4) + (-2r^2 + 3r + 6)
\]
Step 1: Combine the \(r^2\) terms:
\[
2r^2 + (-2r^2) = 0r^2
\]
Step 2: Combine the \(r\) terms:
\[
-3r + 3r = 0r
\]
Step 3: Combine the constant terms:
\[
4 + 6 = 10
\]
Putting it all together, we have:
\[
0r^2 + 0r + 10 = 10
\]
So, the sum of the two polynomial expressions is \(10\).
\[
(2r^2 - 3r + 4) + (-2r^2 + 3r + 6)
\]
Step 1: Combine the \(r^2\) terms:
\[
2r^2 + (-2r^2) = 0r^2
\]
Step 2: Combine the \(r\) terms:
\[
-3r + 3r = 0r
\]
Step 3: Combine the constant terms:
\[
4 + 6 = 10
\]
Putting it all together, we have:
\[
0r^2 + 0r + 10 = 10
\]
So, the sum of the two polynomial expressions is \(10\).
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