To find the atomic mass of \( \text{Fe(OH)}_3 \), we need to calculate the total mass based on the constituents:
- Iron (Fe): The atomic mass of iron is 56 amu.
- Oxygen (O): The atomic mass of oxygen is 16 amu.
- Hydrogen (H): The atomic mass of hydrogen is 1 amu.
In \( \text{Fe(OH)}_3 \):
- There is 1 iron atom: \( 1 \times 56 , \text{amu} = 56 , \text{amu} \)
- There are 3 hydroxide ions (OH), which consist of 1 oxygen and 1 hydrogen:
- For 3 oxygen atoms: \( 3 \times 16 , \text{amu} = 48 , \text{amu} \)
- For 3 hydrogen atoms: \( 3 \times 1 , \text{amu} = 3 , \text{amu} \)
Now, sum these values to get the total atomic mass of \( \text{Fe(OH)}_3 \):
\[ \text{Total mass} = \text{mass of Fe} + \text{mass of O (from OH)} + \text{mass of H (from OH)} \] \[ \text{Total mass} = 56 , \text{amu} + 48 , \text{amu} + 3 , \text{amu} = 107 , \text{amu} \]
Thus, the atomic mass of \( \text{Fe(OH)}_3 \) is 107 amu.