Question
Find the volume of the cone.
4 cm
12 cm
Question content area bottom
Part 1
The volume of the cone is approximately
enter your response here cubic cm.
(Round to the nearest whole number as needed.)
4 cm
12 cm
Question content area bottom
Part 1
The volume of the cone is approximately
enter your response here cubic cm.
(Round to the nearest whole number as needed.)
Answers
GPT-4o mini
To find the volume of a cone, you can use the formula:
\[
V = \frac{1}{3} \pi r^2 h
\]
where \( V \) is the volume, \( r \) is the radius of the base, and \( h \) is the height of the cone.
From your question, it seems that:
- The radius \( r \) = 4 cm
- The height \( h \) = 12 cm
Now, substituting the values into the formula:
\[
V = \frac{1}{3} \pi (4 \text{ cm})^2 (12 \text{ cm})
\]
Calculating \( (4 \text{ cm})^2 \):
\[
(4 \text{ cm})^2 = 16 \text{ cm}^2
\]
Then, substituting that back into the volume formula:
\[
V = \frac{1}{3} \pi (16 \text{ cm}^2)(12 \text{ cm})
\]
Calculating further:
\[
V = \frac{1}{3} \pi (192 \text{ cm}^3)
\]
Now, multiply:
\[
V = \frac{192}{3} \pi \text{ cm}^3
\]
\[
V = 64\pi \text{ cm}^3
\]
Now, using \( \pi \approx 3.14 \):
\[
V \approx 64 \times 3.14 \text{ cm}^3 \approx 200.96 \text{ cm}^3
\]
Rounding to the nearest whole number:
\[
V \approx 201 \text{ cm}^3
\]
So, the volume of the cone is approximately **201 cubic cm**.
\[
V = \frac{1}{3} \pi r^2 h
\]
where \( V \) is the volume, \( r \) is the radius of the base, and \( h \) is the height of the cone.
From your question, it seems that:
- The radius \( r \) = 4 cm
- The height \( h \) = 12 cm
Now, substituting the values into the formula:
\[
V = \frac{1}{3} \pi (4 \text{ cm})^2 (12 \text{ cm})
\]
Calculating \( (4 \text{ cm})^2 \):
\[
(4 \text{ cm})^2 = 16 \text{ cm}^2
\]
Then, substituting that back into the volume formula:
\[
V = \frac{1}{3} \pi (16 \text{ cm}^2)(12 \text{ cm})
\]
Calculating further:
\[
V = \frac{1}{3} \pi (192 \text{ cm}^3)
\]
Now, multiply:
\[
V = \frac{192}{3} \pi \text{ cm}^3
\]
\[
V = 64\pi \text{ cm}^3
\]
Now, using \( \pi \approx 3.14 \):
\[
V \approx 64 \times 3.14 \text{ cm}^3 \approx 200.96 \text{ cm}^3
\]
Rounding to the nearest whole number:
\[
V \approx 201 \text{ cm}^3
\]
So, the volume of the cone is approximately **201 cubic cm**.