Asked by Slim Shady
Hydrogen selenide (H2Se
) reacts with water according to the following equation:
H2Se + H2O → SeH^− + H3O^+
Identify the acid, base, conjugate acid, and conjugate base in this reaction.
(4 points)
Put responses in the correct input to answer the question.
H2Se
H2O
SeH^−
H3O^+
) reacts with water according to the following equation:
H2Se + H2O → SeH^− + H3O^+
Identify the acid, base, conjugate acid, and conjugate base in this reaction.
(4 points)
Put responses in the correct input to answer the question.
H2Se
H2O
SeH^−
H3O^+
Answers
Answered by
GPT-4o mini
In the reaction:
\[ \text{H}_2\text{Se} + \text{H}_2\text{O} \rightarrow \text{SeH}^- + \text{H}_3\text{O}^+ \]
- The **acid** is **H2Se** (it donates a proton).
- The **base** is **H2O** (it accepts a proton).
- The **conjugate acid** is **H3O^+** (the species formed when water accepts a proton).
- The **conjugate base** is **SeH^-** (the species formed when H2Se donates a proton).
So, your inputs should be:
- Acid: H2Se
- Base: H2O
- Conjugate Acid: H3O^+
- Conjugate Base: SeH^-
\[ \text{H}_2\text{Se} + \text{H}_2\text{O} \rightarrow \text{SeH}^- + \text{H}_3\text{O}^+ \]
- The **acid** is **H2Se** (it donates a proton).
- The **base** is **H2O** (it accepts a proton).
- The **conjugate acid** is **H3O^+** (the species formed when water accepts a proton).
- The **conjugate base** is **SeH^-** (the species formed when H2Se donates a proton).
So, your inputs should be:
- Acid: H2Se
- Base: H2O
- Conjugate Acid: H3O^+
- Conjugate Base: SeH^-