A cube has an edge length, a

, that is a rational number of centimeters. Identify which measurement will require the use of irrational numbers.

(1 point)
Responses

the volume of the cube
the volume of the cube

the surface area of the cube
the surface area of the cube

the area of one of the cube’s faces
the area of one of the cube’s faces

the diagonal of one of the cube’s faces

1 answer

To determine which measurement will require the use of irrational numbers, let's analyze each of the options given that the edge length \( a \) of the cube is a rational number:

  1. Volume of the cube: The volume \( V \) of a cube is given by the formula \( V = a^3 \). Since \( a \) is rational, \( a^3 \) will also be rational.

  2. Surface area of the cube: The surface area \( A \) of a cube is given by the formula \( A = 6a^2 \). Since \( a \) is rational, \( 6a^2 \) will also be rational.

  3. Area of one of the cube’s faces: The area of one face \( A_f \) of the cube is given by \( A_f = a^2 \). Since \( a \) is rational, \( a^2 \) will also be rational.

  4. Diagonal of one of the cube’s faces: The diagonal \( d \) of one face (which is a square) can be calculated using the Pythagorean theorem: \( d = a\sqrt{2} \). Here, \( \sqrt{2} \) is an irrational number, so \( d \) will be irrational because it is the product of the rational number \( a \) and the irrational number \( \sqrt{2} \).

Thus, the measurement that will require the use of irrational numbers is:

the diagonal of one of the cube’s faces.