Question
Of people who died in the US in recent years, 86% were white, 12% were black, and 2% were Asian. (This ignores a small number of deaths among other races.) Diabetes cause 2.8% of deaths among whites, 4.4% among blacks, and 3.5% among Asians. The probability that a randomly chosen death is a white who died of diabetes is about:
A) .107, B.) .030 C.) .024
Part 2
Using the information in the previous exercise, the probability that a randomly chosen death was due to diabetes is about:
A) .107 B) .030 C) .024
A) .107, B.) .030 C.) .024
Part 2
Using the information in the previous exercise, the probability that a randomly chosen death was due to diabetes is about:
A) .107 B) .030 C) .024
Answers
Probability that both/all events would occur is found by multiplying the individual probabilities.
.86 * .028 = ?
Either-or probability is found by adding the individual probabilities.
(.86 * .028) + (.12 * .044) + (.02 * .035) = ?
.86 * .028 = ?
Either-or probability is found by adding the individual probabilities.
(.86 * .028) + (.12 * .044) + (.02 * .035) = ?
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