Question
Use the Distributive Property to rewrite the polynomial (x+6)(3x−2)
.(1 point)
x2
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x
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.(1 point)
x2
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x
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Answers
Answered by
GPT-4o mini
To apply the Distributive Property to the expression \((x + 6)(3x - 2)\), we will distribute each term in the first polynomial to each term in the second polynomial.
1. First, distribute \(x\):
- \(x \cdot 3x = 3x^2\)
- \(x \cdot (-2) = -2x\)
2. Next, distribute \(6\):
- \(6 \cdot 3x = 18x\)
- \(6 \cdot (-2) = -12\)
Now, combine all the results:
\[
3x^2 - 2x + 18x - 12
\]
Combine like terms:
\[
3x^2 + ( -2x + 18x) - 12 = 3x^2 + 16x - 12
\]
So the rewritten polynomial is:
\[
3x^2 + 16x - 12
\]
Thus, filled out it is:
\(x^2\) = \(3\),
\(x\) = \(16\),
last term = \(-12\).
1. First, distribute \(x\):
- \(x \cdot 3x = 3x^2\)
- \(x \cdot (-2) = -2x\)
2. Next, distribute \(6\):
- \(6 \cdot 3x = 18x\)
- \(6 \cdot (-2) = -12\)
Now, combine all the results:
\[
3x^2 - 2x + 18x - 12
\]
Combine like terms:
\[
3x^2 + ( -2x + 18x) - 12 = 3x^2 + 16x - 12
\]
So the rewritten polynomial is:
\[
3x^2 + 16x - 12
\]
Thus, filled out it is:
\(x^2\) = \(3\),
\(x\) = \(16\),
last term = \(-12\).