Question
Solve the expression 2(1.6^0
+7)−4.9^0
.
Show your work.
(1 point)
Responses
15
15
14
14
13
13
16
16
+7)−4.9^0
.
Show your work.
(1 point)
Responses
15
15
14
14
13
13
16
16
Answers
GPT-4o mini
To solve the expression \( 2(1.6^0 + 7) - 4 \cdot 9^0 \), we need to follow the order of operations, which involves simplifying the powers first.
1. Calculate \( 1.6^0 \):
- Any number raised to the power of 0 is 1.
- Therefore, \( 1.6^0 = 1 \).
2. Calculate \( 9^0 \):
- Similarly, \( 9^0 = 1 \).
Now we can substitute the calculated values back into the expression:
\[
2(1 + 7) - 4 \cdot 1
\]
3. Simplify the expression inside the parentheses:
- \( 1 + 7 = 8 \).
This gives us:
\[
2(8) - 4 \cdot 1
\]
4. Now, compute \( 2(8) \):
- \( 2 \cdot 8 = 16 \).
So we have:
\[
16 - 4 \cdot 1
\]
5. Calculate \( 4 \cdot 1 \):
- \( 4 \cdot 1 = 4 \).
Thus, our expression is now:
\[
16 - 4
\]
6. Finally, compute \( 16 - 4 \):
- \( 16 - 4 = 12 \).
However, I made a mistake in the calculations earlier; let's redo step 4:
4. Compute \( 2(1 + 7) \) correctly:
\[
2(8) - 4 \cdot 1
\]
This is correctly equals to \( 16 - 4 = 12 \).
So, based on the computations, the final answer for the given expression is:
\(\boxed{12}\).
1. Calculate \( 1.6^0 \):
- Any number raised to the power of 0 is 1.
- Therefore, \( 1.6^0 = 1 \).
2. Calculate \( 9^0 \):
- Similarly, \( 9^0 = 1 \).
Now we can substitute the calculated values back into the expression:
\[
2(1 + 7) - 4 \cdot 1
\]
3. Simplify the expression inside the parentheses:
- \( 1 + 7 = 8 \).
This gives us:
\[
2(8) - 4 \cdot 1
\]
4. Now, compute \( 2(8) \):
- \( 2 \cdot 8 = 16 \).
So we have:
\[
16 - 4 \cdot 1
\]
5. Calculate \( 4 \cdot 1 \):
- \( 4 \cdot 1 = 4 \).
Thus, our expression is now:
\[
16 - 4
\]
6. Finally, compute \( 16 - 4 \):
- \( 16 - 4 = 12 \).
However, I made a mistake in the calculations earlier; let's redo step 4:
4. Compute \( 2(1 + 7) \) correctly:
\[
2(8) - 4 \cdot 1
\]
This is correctly equals to \( 16 - 4 = 12 \).
So, based on the computations, the final answer for the given expression is:
\(\boxed{12}\).