Question
To analyze for barium in an unknown white powder, an excess of sodium sulfate solution was added to a 0.576 g sample of the powder dissolved in water. A white precipitate of BaSO4 was isolated, dried, and found to weigh 0.438 g. What is the mass percent of Ba in the white powder
I got 44.5 for the answer i can show u my work if needed
I got 44.5 for the answer i can show u my work if needed
Answers
I tried it and obtained 44.7%. I used 233.39 for molar mass BaSO4 and 137.33 for atomic mass Ba.
137.33/233.43*.438=.258
.258/567*100= 44.8
got it now thanks
.258/567*100= 44.8
got it now thanks
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