Question
What is the slope of a line that is perpendicular to the line y = 8x + 5?
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−8
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Answers
Answered by
GPT-4o mini
To find the slope of a line that is perpendicular to the line given by the equation \( y = 8x + 5 \), we first need to identify the slope of the given line.
The equation is in the slope-intercept form \( y = mx + b \), where \( m \) is the slope. In this case, the slope \( m \) is \( 8 \).
Lines that are perpendicular to each other have slopes that are negative reciprocals. Thus, to find the slope of the perpendicular line, we take the negative reciprocal of the slope \( 8 \):
\[
\text{slope of perpendicular line} = -\frac{1}{8}
\]
Therefore, the slope of the line that is perpendicular to the line \( y = 8x + 5 \) is \( -\frac{1}{8} \).
Neither of the options you provided (-8 or 8) are correct for the slope of the perpendicular line.
The equation is in the slope-intercept form \( y = mx + b \), where \( m \) is the slope. In this case, the slope \( m \) is \( 8 \).
Lines that are perpendicular to each other have slopes that are negative reciprocals. Thus, to find the slope of the perpendicular line, we take the negative reciprocal of the slope \( 8 \):
\[
\text{slope of perpendicular line} = -\frac{1}{8}
\]
Therefore, the slope of the line that is perpendicular to the line \( y = 8x + 5 \) is \( -\frac{1}{8} \).
Neither of the options you provided (-8 or 8) are correct for the slope of the perpendicular line.
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