What cosecutive whole numbers does the following square root fall between <\(26)<

Answer 1

To find the consecutive whole numbers that the square root of 26 falls between, we need to determine the square roots of the whole numbers surrounding 26.

We know that:

• \(5^2 = 25\)
• \(6^2 = 36\)

Therefore, we can infer that:

\[ 5 < \sqrt{26} < 6 \]

So, the consecutive whole numbers that \(\sqrt{26}\) falls between are \(5\) and \(6\).