Question
The mean weight of an elephant is 244 pounds with a standard deviation of 15 pounds. A herd of elephants were spotted in Africa. An elephant will be randomly selected from the herd. What is the probability that a randomly selected elephant will weigh between 229 and 289?
Answers
GPT-4o mini
To calculate the probability that a randomly selected elephant will weigh between 229 and 289 pounds, we will use the properties of the normal distribution.
Given:
- Mean (\(\mu\)) = 244 pounds
- Standard deviation (\(\sigma\)) = 15 pounds
We will standardize the weights using the z-score formula:
\[
z = \frac{(X - \mu)}{\sigma}
\]
1. **Calculate the z-scores for 229 pounds and 289 pounds.**
For \(X = 229\):
\[
z_{229} = \frac{(229 - 244)}{15} = \frac{-15}{15} = -1
\]
For \(X = 289\):
\[
z_{289} = \frac{(289 - 244)}{15} = \frac{45}{15} = 3
\]
2. **Use the z-table (or standard normal distribution table) to find the probabilities corresponding to these z-scores.**
- For \(z = -1\):
The probability \(P(Z < -1)\) is approximately 0.1587.
- For \(z = 3\):
The probability \(P(Z < 3)\) is approximately 0.9987.
3. **Now, find the probability that a randomly selected elephant weighs between 229 and 289 pounds:**
\[
P(229 < X < 289) = P(Z < 3) - P(Z < -1)
\]
\[
P(229 < X < 289) = 0.9987 - 0.1587 = 0.8400
\]
Thus, the probability that a randomly selected elephant will weigh between 229 and 289 pounds is approximately **0.8400** or **84.00%**.
Given:
- Mean (\(\mu\)) = 244 pounds
- Standard deviation (\(\sigma\)) = 15 pounds
We will standardize the weights using the z-score formula:
\[
z = \frac{(X - \mu)}{\sigma}
\]
1. **Calculate the z-scores for 229 pounds and 289 pounds.**
For \(X = 229\):
\[
z_{229} = \frac{(229 - 244)}{15} = \frac{-15}{15} = -1
\]
For \(X = 289\):
\[
z_{289} = \frac{(289 - 244)}{15} = \frac{45}{15} = 3
\]
2. **Use the z-table (or standard normal distribution table) to find the probabilities corresponding to these z-scores.**
- For \(z = -1\):
The probability \(P(Z < -1)\) is approximately 0.1587.
- For \(z = 3\):
The probability \(P(Z < 3)\) is approximately 0.9987.
3. **Now, find the probability that a randomly selected elephant weighs between 229 and 289 pounds:**
\[
P(229 < X < 289) = P(Z < 3) - P(Z < -1)
\]
\[
P(229 < X < 289) = 0.9987 - 0.1587 = 0.8400
\]
Thus, the probability that a randomly selected elephant will weigh between 229 and 289 pounds is approximately **0.8400** or **84.00%**.