Question
A newborn giant panda has a mass of 9.0 × 10-2 kilograms. An adult male giant anda has a mass of 99 kilograms.
How many times greater is the mass of the adult male giant panda than the mass of the newborn giant panda?
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In scientific notation, the mass of the adult male giant panda is Choose...
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~
times greater.
How many times greater is the mass of the adult male giant panda than the mass of the newborn giant panda?
Use the drop-down menus to write the answer in scientific notation.
Click the arrows to choose an answer from each menu.
Choose...
In scientific notation, the mass of the adult male giant panda is Choose...
Choose...
~
times greater.
Answers
GPT-4o mini
To find out how many times greater the mass of the adult male giant panda is compared to the mass of the newborn giant panda, you divide the mass of the adult panda by the mass of the newborn panda.
Given:
- Mass of the newborn giant panda = \( 9.0 \times 10^{-2} \) kg
- Mass of the adult male giant panda = \( 99 \) kg
Now, perform the division:
\[
\text{Ratio} = \frac{\text{Mass of adult panda}}{\text{Mass of newborn panda}} = \frac{99}{9.0 \times 10^{-2}}
\]
Calculating this, we first rewrite 99 in scientific notation:
\[
99 = 9.9 \times 10^{1}
\]
Now plug this into the ratio:
\[
\text{Ratio} = \frac{9.9 \times 10^{1}}{9.0 \times 10^{-2}}
\]
When dividing numbers in scientific notation, divide the coefficients and subtract the exponents:
\[
\text{Ratio} = \left( \frac{9.9}{9.0} \right) \times 10^{(1 - (-2))}
\]
Calculating \( \frac{9.9}{9.0} \):
\[
\frac{9.9}{9.0} \approx 1.1
\]
And for the exponents:
\[
1 - (-2) = 1 + 2 = 3
\]
Putting this together:
\[
\text{Ratio} \approx 1.1 \times 10^{3}
\]
Now we can express 1.1 in scientific notation.
Thus, the answer is:
In scientific notation, the mass of the adult male giant panda is \( 1.1 \times 10^{3} \) times greater.
Given:
- Mass of the newborn giant panda = \( 9.0 \times 10^{-2} \) kg
- Mass of the adult male giant panda = \( 99 \) kg
Now, perform the division:
\[
\text{Ratio} = \frac{\text{Mass of adult panda}}{\text{Mass of newborn panda}} = \frac{99}{9.0 \times 10^{-2}}
\]
Calculating this, we first rewrite 99 in scientific notation:
\[
99 = 9.9 \times 10^{1}
\]
Now plug this into the ratio:
\[
\text{Ratio} = \frac{9.9 \times 10^{1}}{9.0 \times 10^{-2}}
\]
When dividing numbers in scientific notation, divide the coefficients and subtract the exponents:
\[
\text{Ratio} = \left( \frac{9.9}{9.0} \right) \times 10^{(1 - (-2))}
\]
Calculating \( \frac{9.9}{9.0} \):
\[
\frac{9.9}{9.0} \approx 1.1
\]
And for the exponents:
\[
1 - (-2) = 1 + 2 = 3
\]
Putting this together:
\[
\text{Ratio} \approx 1.1 \times 10^{3}
\]
Now we can express 1.1 in scientific notation.
Thus, the answer is:
In scientific notation, the mass of the adult male giant panda is \( 1.1 \times 10^{3} \) times greater.