3(−2x−1)+x−2=

25

1 answer

To solve the equation \( 3(-2x - 1) + x - 2 = 25 \), we will first distribute the \( 3 \) on the left side:

\[ 3(-2x) + 3(-1) + x - 2 = 25 \] \[ -6x - 3 + x - 2 = 25 \]

Next, we combine like terms on the left side:

\[ -6x + x - 3 - 2 = 25 \] \[ -5x - 5 = 25 \]

Now, we'll isolate \( x \) by first adding \( 5 \) to both sides:

\[ -5x = 25 + 5 \] \[ -5x = 30 \]

Next, divide both sides by \( -5 \):

\[ x = \frac{30}{-5} \] \[ x = -6 \]

Thus, the solution is:

\[ \boxed{-6} \]