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−2(3x−3)+4x−4=

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To solve the equation \(-2(3x - 3) + 4x - 4 = 0\), follow these steps:

  1. Distribute the -2: \[ -2 \cdot 3x + -2 \cdot -3 = -6x + 6 \] So the equation becomes: \[ -6x + 6 + 4x - 4 = 0 \]

  2. Combine like terms: Combine the \(x\) terms and the constant terms: \[ (-6x + 4x) + (6 - 4) = -2x + 2 \] Now the equation is: \[ -2x + 2 = 0 \]

  3. Isolate the variable: Subtract 2 from both sides: \[ -2x = -2 \] Now, divide by -2: \[ x = 1 \]

The solution is \(\boxed{1}\).