Question

Felicia had $80 when she went to a music store that charges $18 for each CD. She needs to have no less than $20 in her wallet when she leaves the store so she has enough money to buy gas for the ride home.

Which shows a possible number of CDs she could buy? Select three options.
1
2
3
4
5

Answer 1

Felicia has $80 and needs to leave with at least $20. This means she can spend a maximum of:

\[ 80 - 20 = 60 \]

Now, since each CD costs $18, we can calculate the maximum number of CDs she can buy:

Let \( x \) be the number of CDs she can buy. The total cost for \( x \) CDs is given by:

\[ 18x \]

To find the maximum number of CDs she can buy while staying within her budget, we set up the following inequality:

\[ 18x \leq 60 \]

Dividing both sides by 18:

\[ x \leq \frac{60}{18} \]

This simplifies to:

\[ x \leq \frac{10}{3} \]

Calculating this gives us approximately:

\[ x \leq 3.33 \]

Since she can only buy a whole number of CDs, she can purchase a maximum of 3 CDs.

Now, let's check the values from 1 to 3 to confirm:

- If Felicia buys **1 CD**: \( 18 \times 1 = 18 \) → Money left: \( 80 - 18 = 62 \) (valid)
- If Felicia buys **2 CDs**: \( 18 \times 2 = 36 \) → Money left: \( 80 - 36 = 44 \) (valid)
- If Felicia buys **3 CDs**: \( 18 \times 3 = 54 \) → Money left: \( 80 - 54 = 26 \) (valid)
- If Felicia buys **4 CDs**: \( 18 \times 4 = 72 \) → Money left: \( 80 - 72 = 8 \) (not valid)
- If Felicia buys **5 CDs**: \( 18 \times 5 = 90 \) → Money left: \( 80 - 90 = -10 \) (not valid)

So the possible numbers of CDs she could buy are **1, 2, or 3**.